=6x^2 - 4x - 9x +6

=(6x^2 -4x) - (9x-6)

=2x(3x -2) - 3(3x-2)

=(3x-2) (2x - 3)

         \(6x^2+13x-15\)

\(=6x^2+18x-5x-15\)

\(=6x.\left(x+3\right)-5.\left(x+3\right)\)

\(=\left(x+3\right).\left(6x-5\right)\)

\(6x^2+13x-15\)

\(=6x^2+18x-5x-15\)

\(=6x\left(x+3\right)-5\left(x+3\right)\)

\(=\left(x+3\right)\left(6x-5\right)\)

\(6x^2+13x-15\)

\(\Rightarrow6x^2+18x-5x-15x\)

\(\Rightarrow6x\times\left(x+3\right)-5\times\left(x+3\right)\)

\(\Rightarrow\left(x+3\right)\times\left(6x-5\right)\)

Code : Breacker

\(P\left(x\right)=6x^3+13x^2+4x-3\)

\(=\left(6x^3+6x^2\right)+\left(7x^2+7x\right)-\left(3x-3\right)\)

\(=6x^2\left(x+1\right)+7x\left(x+1\right)-3\left(x+1\right)\)

\(=\left(6x^2+7x-3\right)\left(x+1\right)\)

\(=\left[\left(6x^2-2x\right)+\left(9x-3\right)\right]\left(x+1\right)\)

\(=\left[2x\left(3x-1\right)+3\left(3x-1\right)\right]\left(x+1\right)\)

\(=\left(3x-1\right)\left(2x+3\right)\left(x+1\right)\)

1) 6x^2 + 7x - 5 

=6x²-3x+10x-5

=3x.(2x-1)+5.(2x-1)

=(2x-1)(3x+5)

2) 10x^2 - 13x - 3

=10x²+2x-15x-3

=2x(5x+1)-3(5x+1)

=(5x+1)(2x-3)

\(6x^2+7x-5\)

\(=6x^2-3x+10x-5\)

\(=3x\left(2x-1\right)+5\left(2x-1\right)\)

\(=\left(2x-1\right)\left(3x+5\right)\)

a) Ta có : 6x² - 13x + 6 = 6x² - 9x - 4x + 6 = 3x(2x - 3) - 2(2x - 3) = (3x - 2)(2x - 3)

b) Ta có: 6x² + 7x - 3 = 6x² + 9x - 2x - 3 = 3x(2x + 3) - (2x + 3) = (3x - 1)(2x + 3)

\(a,6x^2-13x+6\)

\(=6x^2-9x-4x+6\)

\(=3x\cdot\left(2x-3\right)-x\cdot\left(2x-3\right)\)

\(=\left(2x-3\right)\cdot\left(3x-x\right)\)

\(=\left(2x-3\right)\cdot2x\)

\(b,6x^2+7x-3\)

\(=6x^2-2x+9x-3\)

\(=2x\cdot\left(3x-1\right)+3\cdot\left(3x-1\right)\)

\(=\left(3x-1\right)\cdot\left(2x+3\right)\)

\(a,6x^2-13x+6=6x^2-9x-4x+6\)

\(=3x\left(2x-3\right)-2\left(2x-3\right)=\left(2x-3\right)\left(3x-2\right)\)

\(b,6x^2+7x-3=6x^2-2x+9x-3\)

\(=2x\left(3x-1\right)+3\left(3x-1\right)=\left(3x-1\right)\left(2x+3\right)\)

trả lời 

e chưa học đến nha 

nếu ko a lên học 24 hỏi nha 

chúc a học tốt

#)Giải :

a, 16( x - y )² - 49( x + y )²

= [4( x - y )]² - [7( x + y )]²

= [ 4x - 4y ]² - [ 7x + 7y ]²

= ( 4x - 4y + 7x + 7y )[( 4x - 4y ) - ( 7x + 7y )]

= ( 11x - y )( x - 11y )

           #~Will~be~Pens~#

a) \(16\left(x-y\right)^2-49\left(x+y\right)^2\)

\(=\left[4\left(x-y\right)\right]^2-\left[7\left(x+y\right)\right]^2\)

\(=\left[4\left(x-y\right)-7\left(x+y\right)\right]\left[4\left(x-y\right)+7\left(x+y\right)\right]\)

\(=\left(4x-4y-7x-7y\right)\left(4x-4y+7x+7y\right)\)

\(=\left(-3x-11y\right)\left(11x+3y\right)\)

e) \(=x^2\left(x+1\right)-2x\left(x+1\right)+3\left(x+1\right)=\left(x+1\right)\left(x^2-2x+3\right)\)

g) \(=x^2\left(3x-1\right)-x\left(3x-1\right)+4\left(3x-1\right)=\left(3x-1\right)\left(x^2-x+4\right)\)

h) \(=3x^2\left(2x+1\right)-x\left(2x+1\right)+\left(2x+1\right)=\left(2x+1\right)\left(3x^2-x+1\right)\)

i) \(=2x^2\left(2x+1\right)+2x\left(2x+1\right)+\left(2x+1\right)=\left(2x+1\right)\left(2x^2+2x+1\right)\) 

Ta có: \(6x^4-13x^2+6\)

\(=6x^4-9x^2-4x^2+6\)

\(=3x^2\left(2x^2-3\right)-2\left(2x^2-3\right)\)

\(=\left(2x^2-3\right)\left(3x^2-2\right)\)

\(6x^4-13x^2+6=6x^4-4x^2-9x^2+6\)

                         \(=2x^2\left(3x^2-2\right)-3\left(3x^2-2\right)\)

                         \(=\left(2x^2-3\right)\left(3x^2-2\right)\)

Ta có:\(6x^4-13x^2+6\)

\(=6x^4-9x^2-4x^2+6\)

\(=3x^2\left(2x^2-3\right)-2\left(2x^2-3\right)\)

\(=\left(2x^2-3\right)\left(3x^2-2\right)\)